Regular Expression (Regex) For Date part extraction/array split

Needed to use this recently to create a specificity parameter for an API at work, it gives you a key/value array from an ISO date string regardless of what is actually set in the string (e.g. if you give 2011-06-07 04 you’ll get an array back as array(‘year’=>2011, ‘month’ => 6, ‘day’ => 7, ‘hour’ => 4). If you enter 2011-06-07 04:43 you’ll get: array(‘year’=>2011, ‘month’ => 6, ‘day’ => 7, ‘hour’ => 4, ‘minute’ => 43), works from just a year all the way to seconds.

    /**
     * Gets the parts of a date that are set in an ISO date string.
     * 
     * @param string $date date/time to use.
     * 
     * @return array
     */
    public static function getDateParts($date)
    {
        $matches = array();
        preg_match(
            '/(
                (
                    (
                        (
                            (
                                (?<year>d{4})
                                (-(?<month>d{2}))?
                            )
                            (-(?<day>d{2}))?
                        )
                        (s?(?<hour>d{2}))?
                    )
                    (:(?<minute>d{2}))?
                )
                (:(?<second>d{2}))?
            )/x', 
            $date, 
            $matches
        );

        $date = array_map('intval', array_intersect_key($matches, array_flip(array('year', 'month', 'day', 'hour', 'minute', 'second'))));

        return $date;
    }

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